一個將十六進位轉換為二進位字元數組的函數
十六進位數轉換為二進位數組的函數HexToBinStr
函數實現:
void HexToBinStr(int hex, char *bin_str, int str_size)
{
int i;
for (i = 0; i !=str_size; ++i)
{
bin_str[str_size - 1 - i] = hex % 2 + 0;
hex /= 2;
}
}
實際應用:
#include <stdlib.h>
#include <stdio.h>
#define STR_SIZE 14
long hex_value =0xffffef74; //ef74=1110 1111 0111 0100低14位,10 1111 0111 0100
char bin_str[STR_SIZE];
long hex_tmp;
void HexToBinStr(int hex, char *bin_str, int str_size)
{
int i;
for (i = 0; i !=str_size; ++i)
{
bin_str[str_size - 1 - i] = hex % 2 + 0;
hex /= 2;
}
}
int main(void)
{
hex_tmp = hex_value&0x3fff;
HexToBinStr(hex_tmp,bin_str,STR_SIZE);
printf("hex_value: %x, hex_tmp: %x, binstr: %s
",hex_value, hex_tmp, bin_str);
for(int i=0; i< STR_SIZE; i++)
{
printf("%c", bin_str[i]);
}
return 0;
}
實際運行結果: